Here I don't understand,
• why epsilon is visible right in its own initializer,
• and why it is completed just after a digit (1) without any space.
Description
double epsilon = 1e-3;
Typing "1e-" completes into "1epsilon-".
Here I don't understand,
• why epsilon is visible right in its own initializer,
• and why it is completed just after a digit (1) without any space.